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Voltage Drop: Chapter 9, Table 9 Method

Effective Impedance = Ze = [R x COS(θ)] + [XL x SIN(θ)]

θ = Phase Angle, e.g. 31.79 degrees
COS(θ) = COS(31.79) = 0.85 (Which is PF, or Power Factor)
SIN(θ) = SIN(31.79) = 0.527
R = AC Resistance value from Table 9, e.g. 0.054 (See the 250 kcmil line for Steel Conduit)
XL = Reactance value from Table 9, e.g. 0.052 (See the 250 kcmil line for Steel Conduit)
Ze = [0.054 x 0.85] + [0.052 x 0.527] = 0.073 = Effective Impedance

3Ø Phase Voltage Drop, VD = (1.732 x Ze x I x L) / 1000
1Ø Phase Voltage Drop, VD = (2 x Ze x I x L) / 1000

Choose Length Measurement:
Choose Conduit Type:

Power Factor, "PF"
Length in Feet, "L"
Amperes, "I"
Source Voltage, "E"
Choose Wire Size, "CM"

Try the Chapter 9, Table 8 Voltage Drop Calculator and the Easy Voltage Drop Calculator.