_{e}= [R x COS(θ)] + [X

_{L}x SIN(θ)]

θ = Phase Angle, e.g. 31.79 degrees

COS(θ) = COS(31.79) = 0.85 (Which is PF, or Power Factor)

SIN(θ) = SIN(31.79) = 0.527

R = AC Resistance value from Table 9, e.g. 0.054

(See the 250 kcmil line for Steel Conduit)

X_{L} = Reactance value from Table 9, e.g. 0.052

(See the 250 kcmil line for Steel Conduit)

Z_{e} = [0.054 x 0.85] + [0.052 x 0.527] = 0.073 = Effective Impedance

_{e}x I x L) / 1000

1Ø Phase Voltage Drop, VD = (2 x Z

_{e}x I x L) / 1000

Power Factor, "PF"

Length in Feet, "L"

Amperes, "I"

Source Voltage, "E"

Choose Wire Size, "CM"